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10a^2-10a-2000=0
a = 10; b = -10; c = -2000;
Δ = b2-4ac
Δ = -102-4·10·(-2000)
Δ = 80100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80100}=\sqrt{900*89}=\sqrt{900}*\sqrt{89}=30\sqrt{89}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-30\sqrt{89}}{2*10}=\frac{10-30\sqrt{89}}{20} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+30\sqrt{89}}{2*10}=\frac{10+30\sqrt{89}}{20} $
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